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[tex](2\frac{1}{3})^3=(\frac{2\cdot3+1}{3})^3=(\frac{6+1}{3})^3=(\frac{7}{3})^3=\frac{7^3}{3^3}=\frac{7\cdot7\cdot7}{3\cdot3\cdot3}=\frac{343}{27}=12\frac{19}{27}\\\\(\sqrt3)^4=((\sqrt3)^2)^2=3^2=3\cdot3=9[/tex]
