[tex]Dane:\\h = 4\cdot2,7 \ m = 10,8 \ m\\d = 1000\frac{kg}{m^{3}} \ - \ gestosc \ wody\\g = 10\frac{N}{kg}\\Szukane:\\p = ?\\\\p = d\cdot g\cdot h\\\\p = 1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot10,8 \ m\\\\\boxed{p_{min} = 108 \ 000 \ Pa = 108 \ kPa}\\\\(1 \ kPa = 1000 \ Pa)[/tex]
