Rozwiązanie:
[tex]$2\sin\Big(2x-\frac{\pi}{4} \Big)=\sqrt{2}[/tex]
[tex]$\sin\Big(2x-\frac{\pi}{4} \Big)=\frac{\sqrt{2} }{2}[/tex]
[tex]$2x-\frac{\pi}{4} =\frac{\pi}{4} +2k\pi \vee 2x-\frac{\pi}{4} =\frac{3\pi}{4} +2k\pi[/tex]
[tex]$2x=\frac{\pi}{2} +2k\pi \vee 2x=\pi +2k\pi[/tex]
[tex]$x=\frac{\pi}{4} +k\pi \vee x=\frac{\pi}{2} +k\pi[/tex]
[tex]k \in \mathbb{Z}[/tex]
