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[tex]2\frac{2}{7}\cdot7-(3\frac{1}{2})^2=\frac{2\cdot7+2}{7}\cdot7-(\frac{3\cdot2+1}{2})^2=\frac{14+2}{7}\cdot7-(\frac{6+1}{2})^2=\\\\=\frac{16}{7}\cdot7-(\frac{7}{2})^2=16-\frac{7^2}{2^2}=16-\frac{7\cdot7}{2\cdot2}=16-\frac{49}{4}=16-12\frac{1}{4}=3\frac{3}{4}[/tex]
