Cześć!
1)
[tex]1\frac{1}{8}+a=1\frac{1}{4}\\\\a=1\frac{1}{4}-1\frac{1}{8}\\\\a=1\frac{2}{8}-1\frac{1}{8}\\\\\boxed{a=\frac{1}{8}}[/tex]
2)
[tex]b-\frac{1}{3}=\frac{1}{6}\\\\b=\frac{1}{6}+\frac{1}{3}\\\\b=\frac{1}{6}+\frac{2}{6}\\\\b=\frac{3}{6}\\\\\boxed{b=\frac{1}{2}}[/tex]
3)
[tex]c+\frac{3}{7}=1\frac{9}{14}\\\\c=1\frac{9}{14}-\frac{3}{7}\\\\c=1\frac{9}{14}-\frac{6}{14}\\\\\boxed{c=1\frac{3}{14}}[/tex]
4)
[tex]d-\frac{1}{2}=\frac{5}{6}\\\\d=\frac{5}{6}+\frac{1}{2}\\\\d=\frac{5}{6}+\frac{3}{6}=\frac{8}{6}=\frac{4}{3}\\\\\boxed{d=1\frac{1}{3}}[/tex]
5)
[tex]2\frac{1}{6}+x=2\frac{1}{3}\\\\x=2\frac{1}{3}-2\frac{1}{6}\\\\x=2\frac{2}{6}-2\frac{1}{6}\\\\\boxed{x=\frac{1}{6}}[/tex]
6)
[tex]y-\frac{1}{2}=1\frac{3}{4}\\\\y=1\frac{3}{4}+\frac{1}{2}\\\\y=1\frac{3}{4}+\frac{2}{4}=1\frac{5}{4}\\\\\boxed{y=2\frac{1}{4}}[/tex]
7)
[tex]\frac{11}{12}-z=\frac{2}{3}\\\\z=\frac{11}{12}-\frac{2}{3}\\\\z=\frac{11}{12}-\frac{8}{12}=\frac{3}{12}\\\\\boxed{z=\frac{1}{4}}[/tex]
8)
[tex]\frac{7}{10}-t=\frac{2}{5}\\\\t=\frac{7}{10}-\frac{2}{5}\\\\t=\frac{7}{10}-\frac{4}{10}\\\\\boxed{t=\frac{3}{10}}[/tex]
