Wzór na pole prostokąta o bokach a i b to: [tex]P=ab[/tex]
A] [tex]a=\sqrt{2}[/tex] i [tex]b=3\sqrt{2}[/tex] więc: [tex]P=\sqrt{2}\cdot 3\sqrt{2}=3\sqrt{4}=3\cdot2=6[/tex]
pole wynosi [tex]6 cm^2[/tex]
B] [tex]a=\sqrt{3}[/tex] i [tex]b=\sqrt{12} =\sqrt{4\cdot3}=2 \sqrt{3}[/tex] więc: [tex]P=\sqrt{3}\cdot2 \sqrt{3}=2 \sqrt{9}=2\cdot3=6[/tex]
pole wynosi [tex]6cm^2[/tex]
Wzór na obwód prostokąta o tych samych bokach to: [tex]l=2(a+b)[/tex]
A] [tex]l=2(\sqrt{2}+3\sqrt{2})=2\cdot4\sqrt{2}=8\sqrt{ 2}[cm][/tex]
B] [tex]l=2(\sqrt{3}+ 2\sqrt{3})=2\cdot3\sqrt{3}=6\sqrt{3}[cm][/tex]
