[tex]\left \{ {{5x+y=8/-5x} \atop {4x+3y=2}} \right. \\\left \{ {{y=8-5x} \atop {4x+3y=2}} \right. \\\left \{ {{y=8-5x} \atop {4x+3*(8-5x)=2}} \right. \\\left \{ {{y=8-5x} \atop {4x+24-15x=2} /-24} \right. \\\left \{ {{y=8-5x} \atop {-11x=-22 /:(-11)}} \right. \\\left \{ {{y=8-5x} \atop {x=2}} \right. \\\left \{ {{y=8-5*2} \atop {x=2}} \right. \\\left \{ {{y=8-10} \atop {x=2}} \right. \\\left \{ {{y=-2} \atop {x=2}} \right.[/tex]
Odp. D
Sprawdzenie metoda przeciwnych wspolczynnikow
[tex]\left \{ {{5x+y=8 /*(-3)} \atop {4x+3y=2}} \right. \\+\left \{ {{-15x-3y=-24} \atop {4x+3y=2}} \right. \\-15x+4x=-24+2\\-11x=-22 /:(-11)\\x=2[/tex]
