[tex]dane:\\m = 2 \ kg\\g_{Z} = 10\frac{N}{kg}\\g_{M} = \frac{2}{5}g_{Z} = \frac{2}{5}\cdot10\frac{N}{kg} = 4\frac{N}{kg}\\szukane:\\F_{M} = ?\\\\F_{M} = m\cdot g_{M}\\\\F_{M} = 2 \ kg\cdot4\fra{N}{kg}\\\\\boxed{F_{M} = 8 \ N}[/tex]
Odp. Ciężar tego ciała na powierzchni Marsa wynosi 8 N.
