Odpowiedź :
[tex]Dane:\\m = 4 \ kg\\T_1 = 30^{o}C\\T_2 = 100^{o}C\\\Delta T = T_2 - T_1 = 100^{o}C - 30^{o}C = 70^{o}C\\c_{w} = 4200\frac{J}{kg\cdot^{o}C}\\szukane:\\Q = ?\\\\Q = c_{w}\cdot m\cdot \Delta T\\\\Q = 4200\frac{J}{kg\cdot^{o}C}\cdot4 \ kg\cdot70^{o}C\\\\\boxed{Q = 1 \ 176 \ 000 \ J = 1 \ 176 \ kJ}\\\\Odp. \ D.[/tex]