Odpowiedź:
zad. 2
a)
[tex] \frac{1}{ \sqrt{5} } = \frac{1 \times \sqrt{5} }{ \sqrt{5} \times \sqrt{5} } = \frac{1 \sqrt{5} }{5} [/tex]
b)
[tex] \frac{4}{ \sqrt{11} } = \frac{4 \times \sqrt{11} }{ \sqrt{11} \times \sqrt{11} } = \frac{4 \sqrt{11} }{11} [/tex]
c)
[tex] \frac{4}{ \sqrt{2} } = \frac{4 \times \sqrt{2} }{ \sqrt{2} \times \sqrt{2} } = \frac{4 \sqrt{2} }{2} = 2 \sqrt{2} [/tex]
d)
[tex] \frac{6}{ \sqrt{3} } = \frac{6 \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} } = \frac{6 \sqrt{3} }{3} = 2 \sqrt{3} [/tex]
e)
[tex] \frac{3}{2 \sqrt{7} } = \frac{3 \times \sqrt{7} }{2 \sqrt{7} \times \sqrt{7} } = \frac{3 \sqrt{7} }{2 \times 7} = \frac{3 \sqrt{7} }{14} [/tex]
f)
[tex] \frac{9}{2 \sqrt{3} } = \frac{9 \times \sqrt{3} }{2 \sqrt{3} \times \sqrt{3} } = \frac{9 \sqrt{3} }{2 \times 3} = \frac{9 \sqrt{3} }{6} = \frac{3 \sqrt{3} }{2} [/tex]
zad. 3
1. S
[tex] \frac{3}{ \sqrt{15} } = \frac{3 \sqrt{15} }{15} = \frac{ \sqrt{15} }{5} [/tex]
2. Z
[tex] \frac{15}{ \sqrt{3} } = \frac{15 \sqrt{3} }{3} = 5 \sqrt{3} [/tex]
3. A
[tex] \frac{1}{ \sqrt{15} } = \frac{ \sqrt{15} }{15} [/tex]
4. L
[tex] \frac{15}{ \sqrt{15} } = \frac{15 \sqrt{15} }{15} = \sqrt{15} [/tex]
5. K
[tex] \frac{5}{ \sqrt{15} } = \frac{5 \sqrt{15} }{15} = \frac{ \sqrt{15} }{3} [/tex]
6. I
[tex] \frac{15}{ \sqrt{5} } = \frac{15 \sqrt{5} }{5} = 3 \sqrt{5} [/tex]
SZALKI
