[tex]3(|2x+3|+2)<10+|2x+3|\\\\3|2x+3|+6<10+|2x+3|\\\\3|2x+3|-|2x+3|<10-6\\\\2|2x+3|<4\\\\|2x+3|<2\\\\2x+3<2\quad\text{i}\quad 2x+3>-2\\\\2x<-1\quad\text{i}\quad 2x>-5\\\\x<-\dfrac{1}{2}\quad\text{i}\quad x>-\dfrac{5}{2}\\\\\boxed{x\in\Big(-\dfrac{5}{2},-\dfrac{1}{2}\Big)}[/tex]
