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Rozwiąż potęgi


[tex] {4}^{2} \times {2}^{5} \div 64 = [/tex]
[tex] {3}^{7} \div (9 \times 27) = [/tex]
[tex] {3}^{2} \times {3}^{6} \div 81 + 1 = [/tex]
[tex]64 \div {2}^{3} \times 4 = [/tex]



Odpowiedź :

Wykorzystamy wzory:

[tex]a^m\cdot a^n=a^{m+n}\\\\a^m : a^n=a^{m-n}\\\\(a^m)^n=a^{m\cdot n}[/tex]

Zadanie 1

[tex]4^2\cdot 2^5:64=(2^2)^2\cdot2^5:2^6=2^4\cdot2^5:2^6=2^{4+5-6}=2^3=\boxed{8}[/tex]

Zadanie 2

[tex]3^7:(9\cdot27)=3^7:(3^2\cdot3^3)=3^7:3^{2+3}=3^7:3^5=3^{7-5}=3^2=\boxed{9}[/tex]

Zadanie 3

[tex]3^2\cdot3^6:81+1=3^{2+6}:3^4+1=3^8:3^4+1=3^{8-4}+1=3^4+1=81+1=\boxed{82}[/tex]

Zadanie 4

[tex]64:2^3\cdot4=2^6:2^3\cdot2^2=2^{6-3+2}=2^5=\boxed{32}[/tex]