Odpowiedź :
Cześć!
Obliczenia
[tex]f(x)=x^2-7; \ f(x)=29\\\\x^2-7=29\\\\x^2=29+7\\\\x^2=36\\\\x_1=\sqrt{36}=6 \ \ \ \vee \ \ \ x_2=-\sqrt{36}=-6\\\\\huge\boxed{\text{Odp}. \text{C}}[/tex]
Cześć!
Obliczenia
[tex]f(x)=x^2-7; \ f(x)=29\\\\x^2-7=29\\\\x^2=29+7\\\\x^2=36\\\\x_1=\sqrt{36}=6 \ \ \ \vee \ \ \ x_2=-\sqrt{36}=-6\\\\\huge\boxed{\text{Odp}. \text{C}}[/tex]