[tex]zad.1\\\\4^{3} \cdot \dfrac{1}{16} -5\cdot \dfrac{1}{25} = 4\cdot 16 \cdot \dfrac{1}{16} -5\cdot \dfrac{1}{5\cdot 5} =4-\dfrac{1}{5}=3\dfrac{5}{ 5}-\dfrac{1}{5}=3\dfrac{4}{5}=3\dfrac{8}{10}=3,8[/tex]
[tex]lub~~inna~~metoda:\\\\4^{3}\cdot \dfrac{1}{16} -5\cdot \dfrac{1}{25} =\dfrac{4^{3} }{16} -\dfrac{5}{25} =\dfrac{4^{3} }{4^{2} } -\dfrac{5^{1} }{5^{2} }=4^{3-2} -5^{1-2} =4^{1} -5^{-1}=4-\dfrac{1}{5} =4-\dfrac{2}{10} =4-0,2=3,8[/tex]
korzystam ze wzoru:
[tex]\dfrac{x^{n} }{x^{m} } =x^{n}\div x^{m}=x^{n-m}[/tex]
