Odpowiedź :
a)
t= 15 min = 15*60s = 900 s
q=340C
I = q/t = 340C/900s = 17/45 A ≈ 0,378 A
b)
t=3h = 3*3600s = 10800s
q=2808C
I = q/t = 2808C/10800s = 0,26 A
c)
t=30 min = 30*60s=1800s
q=43C
I = q/t = 43C/1800s= 43/1800 A ≈ 0,0239 A = 23,9 mA
a)
t= 15 min = 15*60s = 900 s
q=340C
I = q/t = 340C/900s = 17/45 A ≈ 0,378 A
b)
t=3h = 3*3600s = 10800s
q=2808C
I = q/t = 2808C/10800s = 0,26 A
c)
t=30 min = 30*60s=1800s
q=43C
I = q/t = 43C/1800s= 43/1800 A ≈ 0,0239 A = 23,9 mA