[tex]a)\\\\\sqrt{6-\sqrt{6-\sqrt{4}}}=\sqrt{6-\sqrt{6-2}}=\sqrt{6-\sqrt{4}}=\sqrt{6-2}=\sqrt{4}=2\\\\b)\\\\\sqrt{15}*\sqrt{\frac{5}{5}}=\sqrt{15}*\sqrt{1}=\sqrt{15}*1=\sqrt{15}\\\\c)\\\\\sqrt[3]{20}*\sqrt[3]{\frac{2}{5}}=\sqrt[3]{\not{20}^4*\frac{2}{\not{5}^1}}=\sqrt[3]{8}=2[/tex]
[tex]d)\\\\ (\sqrt{50}:\sqrt{54} )*\sqrt{3}=\sqrt{50:54}*\sqrt{3}=\sqrt{\frac{50}{\not {54}^{18}}*\not{3}^1 }=\sqrt{\frac{50}{18}}=\sqrt{\frac{25}{9}}=\frac{5}{3}=1\frac{2}{3}\\\\e)\\\\\sqrt{8}*\sqrt{2}-\sqrt{12}*\sqrt{3}=\sqrt{8*2}-\sqrt{12*3}=\sqrt{16}-\sqrt{36}=4-6=-2\\\\stosujemy\ wzory:\\\\\\\sqrt{a}*\sqrt{b} =\sqrt{a*b}\\\\\sqrt{a}:\sqrt{b} =\sqrt{a:b}[/tex]
