pls szybko pomoc kkkk

12.
[tex]a) \ \sqrt{12} = \sqrt{4\cdot3} = \sqrt{4}\cdot\sqrt{3} = 2\sqrt{3}\\\\b) \ \sqrt{20} = \sqrt{4\cdot5} = \sqrt{4}\cdot\sqrt{5} = 2\sqrt{5}\\\\c) \ \sqrt{50} = \sqrt{25\cdot2} = \sqrt{25}\cdot\sqrt{2} = 5\sqrt{2}\\\\d) \ \sqrt{180} = \sqrt{36\cdot5} =\sqrt{36}\cdot\sqrt{5} = 6\sqrt{5}\\\\e) \ \sqrt[3]{16} = \sqrt[3]{8\cdot2} = \sqrt[3]{8}\cdot\sqrt[3]{2} = 2\sqrt[3]{2}\\\\f) \ \sqrt[3]{2000} = \sqrt[3]{1000\cdot2} = \sqrt[3]{1000}\cdot\sqrt[3]{2} = 10\sqrt[3]{2}[/tex]
Odpowiedź:
Szczegółowe wyjaśnienie:
a)
√12 = √(4 *3) = √(2²*3) = 2√3
b)
√20 = √(4 * 5) = √(2²* 5) = 2√5
c)
√50 = √(25 * 2) = √(5² * 2) = 5√2
d)
√180 = √(36 * 5) = √(6²* 5) = 6√5
e)
³√16 = ³√(8 * 2) = ³√(2³ * 2) = 2 ³√2
f)
³√2000 = ³√(1000 * 2) = ³√(10³ * 2) = 10 ³√2