Odpowiedź:
a) x(x-2) + 3([tex]x^{2}[/tex]-x)+3 = [tex]x^{2}[/tex]-2x+3[tex]x^{2}[/tex]-3x+3 = 4[tex]x^{2}[/tex]-5x-3
b) [tex]\frac{1}{2}(4x-6) -(-x+1) = \frac{4}{2} x-\frac{6}{2} +x-1=2x-3+x-1=3x-4[/tex]
c) 5(x-y-1)-4(x+2)=5x-5y-5-4x-8= x-5y-13
d) -(x-6)-3(-x-4)= -x+6+3x+12=2x+18
e)10(x-4)-2= 10x-40-2=10x-42
f) -10(x-4)-2 = -10x+40-2= -10x+38
g) 10(-x+4)-2 = -10x+40-2= - 10x +38
h) -10 (-x-4) -2 = 10x+40-2= 10x + 38
Szczegółowe wyjaśnienie:
