Odpowiedź :
[tex]\sin\alpha\cos\alpha=\frac{3}{8}\\\\(\sin\alpha-\cos\alpha)^2+2=\sin^2\alpha-2\sin\alpha\cos\alpha+\cos^2\alpha+2=\\=\sin^2\alpha+\cos^2\alpha+2-2\sin\alpha\cos\alpha=1+2-2\cdot\frac{3}{8}=3-\frac{3}{4}=2\frac{1}{4}=2,25[/tex]
[tex]\sin\alpha\cos\alpha=\frac{3}{8}\\\\(\sin\alpha-\cos\alpha)^2+2=\sin^2\alpha-2\sin\alpha\cos\alpha+\cos^2\alpha+2=\\=\sin^2\alpha+\cos^2\alpha+2-2\sin\alpha\cos\alpha=1+2-2\cdot\frac{3}{8}=3-\frac{3}{4}=2\frac{1}{4}=2,25[/tex]