Odpowiedź :
[tex]|2-|x+1||\leq3\\2-|x+1|\leq3 \wedge 2-|x+1|\geq-3\\|x+1|\geq-1 \wedge |x+1|\leq5\\x\in\mathbb{R} \wedge x+1\leq 5 \wedge x+1\geq-5 \\x\in\mathbb{R} \wedge x\leq 4 \wedge x\geq-6 \\x\in\langle-6,4\rangle[/tex]
[tex]|2-|x+1||\leq3\\2-|x+1|\leq3 \wedge 2-|x+1|\geq-3\\|x+1|\geq-1 \wedge |x+1|\leq5\\x\in\mathbb{R} \wedge x+1\leq 5 \wedge x+1\geq-5 \\x\in\mathbb{R} \wedge x\leq 4 \wedge x\geq-6 \\x\in\langle-6,4\rangle[/tex]