Prosze pilnie o pomoc w zadaniu 2 DAJE NAJ prosze o obliczenia

[tex]P=\dfrac{a^2\sqrt{3}}{4}\\\\\\a)\ \ a=0,6\\\\P=\dfrac{0,6^2\sqrt{3}}{4}=\dfrac{\not0,36^{0,09}\sqrt{3}}{\not4_{1}}=0,09\sqrt{3}\\\\\\b)\ \ a=1\frac{3}{5}\\\\P=\dfrac{(1\frac{3}{5})^2\sqrt{3}}{4}=\dfrac{(\frac{8}{5})^2\sqrt{3}}{4}=\dfrac{\frac{64}{25}\sqrt{3}}{4}=\frac{64}{25}\sqrt{3}:4=\frac{64}{25}\sqrt{3}\cdot\frac{1}{4}=\frac{64}{100}\sqrt{3}=0,64\sqrt{3}[/tex]

[tex]c)\ \ a=2\sqrt{2}\\\\P=\dfrac{(2\sqrt{2})^2\sqrt{3}}{4}=\dfrac{4\cdot2\sqrt{3}}{4}=\dfrac{\not8^2\sqrt{3}}{\not4_{1}}=2\sqrt{3}\\\\\\d)\ \ a=3\sqrt{3}\\\\P=\dfrac{(3\sqrt{3})^2\sqrt{3}}{4}=\dfrac{9\cdot3\sqrt{3}}{4}=\dfrac{27\sqrt{3}}{4}=6,75\sqrt{3}\\\\\\e)\ \ a=4\sqrt{5}\\\\P=\dfrac{(4\sqrt{5})^2\sqrt{3}}{4}=\dfrac{16\cdot5\sqrt{3} }{4}=\dfrac{\not80^2^0\sqrt{3}}{\not4_{1}}=20\sqrt{3}[/tex]

Basetlago Basetlago · Answer 2

[tex]P = \frac{a^{2}\sqrt{3}}{4}[/tex]

[tex]a) \ a = 0,6\\\\P = \frac{0,6^{2}\cdpt\sqrt{3}}{4} = \frac{0,36\sqrt{3}}{4} = 0,9\sqrt{3}\\\\\\b) \ a = 1\frac{3}{5} = \frac{8}{5}\\\\P = \frac{(\frac{8}{5})^{2}\sqrt{3}}{4} = \frac{\frac{64}{25}\sqrt{3}}{4}=\frac{64\sqrt{3}}{100} = \frac{16\sqrt{3}}{25}\\\\\\c) \ a = 2\sqrt{2}\\\\P = \frac{(2\sqrt{2})^{2}\cdot\sqrt{3}}{4} =\frac{8\sqrt{3}}{4} = 2\sqrt{3}\\\\\\d) \ a = 3\sqrt{3}\\\\P = \frac{(3\sqrt{3})^{2}\cdot\sqrt{3}}{4} = \frac{27\sqrt{3}}{4}\\\\\\e) \ a = 4\sqrt{5}[/tex]

[tex]P = \frac{(4\sqrt{5})^{2}\cdot\sqrt{3}}{4} = \frac{80\sqrt{3}}{4} = 20\sqrt{3}[/tex]