matma powrórkomat kl 8

Odpowiedź:
a.
[tex]14 \frac{1}{3} + ( - 10 \frac{1}{6} ) = 14 \frac{2}{6} + ( - 10 \frac{1}{6} ) = 4 \frac{1}{6} [/tex]
b.
[tex]7 \frac{1}{2} \div \frac{5}{3} = \frac{15}{2} \times \frac{3}{5} = \frac{9}{2} = 4 \frac{1}{2} [/tex]
c.
[tex] - {6}^{2} \times ( - \frac{1}{8} ) = - 36 \times ( - \frac{1}{8} ) = 4[/tex]
d.
[tex] - 7 \frac{1}{6} + 11 \frac{5}{36} = - 7 \frac{6}{36} + 11 \frac{5}{36} = 4 \frac{1}{36} [/tex]
odp. c