Odpowiedź:
[tex]a)\ \ \dfrac{2^8+2^6}{20}=\dfrac{2^2\cdot2^6+2^6}{20}=\dfrac{2^6(2^2+1)}{20}=\dfrac{2^6(4+1)}{20}=\dfrac{2^6\cdot\not5^1}{\not20_{4}}=\dfrac{2^6}{4}=\dfrac{2^6}{2^2}=\\\\\\=2^{6-2}=2^4=16\\\\\\b)\ \ \dfrac{2^7\cdot9^3}{6^5}=\dfrac{2^7\cdot(3^2)^3}{2^5\cdot3^5}=\dfrac{2^7\cdot3^6}{2^5\cdot3^5}=2^{7-5}\cdot3^{6-5}=2^2\cdot3^1=4\cdot3=12[/tex]
