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6. Oblicz: a) 5. 7+19 10 14-9 0) 3. e) 34 16 10 12 1483 역 7-3 b) 6, 3 d) 211 +7 7 f 1) (14. 81,11%): 8. 3​

6 Oblicz A 5 719 10 149 0 3 E 34 16 10 12 1483 역 73 B 6 3 D 211 7 7 F 1 14 8111 8 3 class=

Odpowiedź :

[tex]e) \;\frac{8}{9-4} :\frac{16-10}{12} =\frac{8}{5} :\frac{6}{12} = \frac{\not8^{4} }{5} *\frac{12}{\not6^{3} } =\frac{48}{15} =3\frac{\not3^{1} }{\not15^{5} } = \boxed{3\frac{1}{5} }\\\\f)\;(14 * \frac{81-17}{21} ) :\frac{8}{3} =(14*\frac{64}{21} ):\frac{8}{3} = (\frac{\not14^{2} }{1} * \frac{64}{\not21^{3} } ) :\frac{8}{3} = \frac{128}{3} : \frac{8}{3} = \frac{\not128^{16} }{\not3^{1} } *\frac{\not3^{1} }{\not8^{1} } = \boxed{16}[/tex]

[tex]c) \frac{\frac{2}{3 } + \frac{1 }{2} -0,5}{0,2-0,8*\frac{1}{8} } = \frac{\frac{2}{3}+\frac{1}{2}-\frac{1}{2} }{\frac{1}{5}-\frac{3}{5} *\frac{1}{8} } =\frac{\frac{2}{3} }{\frac{1^{*7} }{5_{*7} }-\frac{3^{*1} }{40_{*1} } } =\frac{\frac{2}{3} }{\frac{7}{40} - \frac{3}{40} } =\frac{\frac{2}{3} }{\frac{\not4^{1} }{\not40^{8} } }= \frac{2}{3} :\frac{1}{8} =\frac{2}{3} *\frac{8}{1} = \frac{16}{3} = \boxed{5\frac{1}{3}}[/tex]