Odpowiedź:
Zad5
a) 3a(2b+4)+2a(3-5b)=6ab+12a+6a-10ab=(-4ab)+18a
-2x(5x-y)-x(8x-2y)=(-10x)+2xy-8x²+2xy=(-10x)-8x²+4xy
5p(2+3r-p)-3p(2p-4)=10p+15pr-5p²-6p²-12p=(-2p)+15pr-11p²
3k(4-5m+2k)-3m(2-3k)=12k-15km+6k²-6m+9km=12k-6km+6k²-6m
b)(2a+b)(3a+5)=6a²+10a+18a+30=6a²+28a+30
(3p-2)(5p+4)=15p²+12p-10p-8=15p²+2p-8
(2x-3)(5x-1)=10x²-2x-15x+3=10x²-17x+3
(3y-2)(4-3y)=12y-9y²-8+6y=18y-9y²-8
Szczegółowe wyjaśnienie:
