Odpowiedź :
Odpowiedź:
[tex](2a+6)(3a+5)=6a^2+10a+18a+30=6a^2+28a+30\\\\\\(3p-2)(5p+4)=15p^2+12p-10p-8=15p^2+2p-8\\\\\\(2x-3)(5x-1)=10x^2-2x-15x+3=10x^2-17x+3\\\\\\(3y-2)(4-3y)=12y-9y^2-8+6y=-9y^2+18y-8\\\\\\x(3x+6)+(x-4)(2x+1)=3x^2+6x+2x^2+x-8x-4=5x^2-x-4\\\\\\2a(5a-3)-(2a+3)(a+4)=10a^2-6a-(2a^2+8a+3a+12)=\\\\=10a^2-6a-2a^2-8a-3a-12=8a^2-17a-12\\\\\\(3u-2)(2u-1)-5u(2u+3)=6u^2-3u-4u+2-10u^2-15u=-4u^2-22u+2[/tex]