Odpowiedź:
[tex]a)\ \ 4^{\frac{3}{2}}=(\sqrt{4})^3=2^3=8\\\\b)\ \ 27^{\frac{2}{3}}=(\sqrt[3]{27})^2=3^2=9\\\\c)\ \ 8^{\frac{4}{3}}=(\sqrt[3]{8})^4=2^4=16\\\\d)\ \ 32^{\frac{3}{5}}=(\sqrt[5]{32})^3=2^3=8\\\\e)\ \ 81^{1,5}=81^{\frac{15}{10}}=81^{\frac{3}{2}}=(\sqrt{81})^3=9^3=729\\\\f)\ \ 4^{2,5}=4^{\frac{25}{10}}=4^{\frac{5}{2}}=(\sqrt{4})^5=2^5=32[/tex]
[tex]g)\ \ 125^{-\frac{2}{3}}=(\frac{1}{125})^{\frac{2}{3}}=\left(\sqrt[3]{\frac{1}{125}} }\right)^2=(\frac{1}{5})^2=\frac{1}{25}\\\\h)\ \ (\frac{1}{81})^{-\frac{3}{4}}=81^{\frac{3}{4}}=(\sqrt[4]{81})^3=3^3=27\\\\i)\ \ (\frac{1}{4})^{-2,5}=4^{2,5}=4^{\frac{25}{10}}=4^{\frac{5}{2}}=(\sqrt{4})^5=2^5=32\\\\j)\ \ (\frac{8}{27})^{-\frac{2}{3}}=(\frac{27}{8})^{\frac{2}{3}}=\left(\sqrt[3]{\frac{27}{8}}\right)^2=(\frac{3}{2})^2=\frac{9}{4}=2\frac{1}{4}[/tex]
