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Zapisz w postaci jak naprostszej sumy algebraicznej. Na jutro!!!

B) (2a +6) (3a +5) =
(3p- 2) (5p + 4) =
(2x -3) (5x - 1) =
(3y - 2) (4-3y) =


Odpowiedź :

[tex](2a+6)(3a+5)=\\=6a^2+10a+18a+30=\\=\boxed{6a^2+28a+30}\\\\(3p-2)(5p+4)=\\=15p^2+12p-10p-8=\\=\boxed{15p^2+2p-8}\\\\(2x-3)(5x-1)=\\=10x^2-2x-15x+3=\\=\boxed{10x^2-17x+3}\\\\(3y-2)(4-3y)=\\=12y-9y^2-8+6y=\\=\boxed{-9y^2+18y-8}[/tex]