Odpowiedź:
Zad: 16
D
zad: 17
a) 4[tex]\sqrt{5}[/tex] * [tex]\sqrt{6}[/tex] = 4[tex]\sqrt{30}[/tex]
b) [tex]\frac{12\sqrt{10} }{3\sqrt{2} }[/tex] = [tex]\frac{12\sqrt{5} *\sqrt{2} }{3\sqrt{2} }[/tex] = 4[tex]\sqrt{5}[/tex]
c) 5[tex]\sqrt[3]{12}[/tex]
d) [tex]\frac{16\sqrt[n3]{-6} *\sqrt[3]{-2} }{8\sqrt[3]{-2} }[/tex] = 2[tex]\sqrt[3]{-6}[/tex]
Zadanie 20
a) 12 + 4 = 16
b) [tex]\sqrt[3]{144+856}[/tex] = [tex]\sqrt[3]{1000}[/tex] = 10
c) 15 + 7 = 22
d) [tex]\frac{\sqrt{16*2} + 2\sqrt{2} }{\sqrt{2} }[/tex] = [tex]\frac{4\sqrt{2} + 2\sqrt{2} }{\sqrt{2} } = \frac{6\sqrt{2} }{\sqrt{2} } = 6[/tex]
e) [tex]\sqrt[3]{8} + \sqrt{36} = 2+ 6 = 8[/tex]
Szczegółowe wyjaśnienie:
