daje naj proszę o pomoc potrzebuje do 24

[tex]f) 1\frac{1}{2}-\frac{1}{3}=\frac{3}{2}-\frac{1}{3}=\frac{9}{6}-\frac{2}{6}=\frac{7}{6}=1\frac{1}{6}\\\\g) 1\frac{1}{2}+\frac{3}{8}=\frac{3}{2}+\frac{3}{8}=\frac{12}{8} +\frac{3}{8}=\frac{15}{8}=1\frac{7}{8}\\\\h) 1\frac{1}{3}-\frac{2}{9}=\frac{4}{3}-\frac{2}{9}=\frac{12}{18}-\frac{4}{18}=\frac{8}{18}=\frac{4}{9}\\\\i) 2\frac{3}{5}-\frac{7}{10}=\frac{13}{5}-\frac{7}{10}=\frac{26}{10}-\frac{7}{10}=\frac{21}{10}=2\frac{1}{10}\\\\[/tex]Odpowiedź:
[tex]a) \frac{1}{7}+\frac{5}{14}= \frac{2}{14}+ \frac{5}{14}=\frac{7}{14} =\frac{1}{2} \\\\b) \frac{3}{4}+\frac{5}{12}=\frac{9}{12}+\frac{5}{12}=\frac{14}{12} =1\frac{2}{12}=1\frac{1}{6}\\\\c)\frac{8}{9}-\frac{5}{18}=\frac{16}{18}-\frac{5}{18}=\frac{11}{8}=1\frac{2}{8}=1\frac{1}{4}\\\\d) \frac{1}{3}+\frac{3}{4}=\frac{4}{12}+\frac{9}{12}=\frac{13}{12}=1\frac{1}{12}\\\\e) \frac{3}{5}-\frac{1}{2}= \frac{6}{10} -\frac{5}{10}=\frac{1}{10}\\\\[/tex]
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