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KirKugo
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Potrzebuje pomocy ;c
na szybko
daje naj

Potrzebuje Pomocy C Na Szybko Daje Naj class=

Odpowiedź :

Asiunia1312go

Odpowiedź:

Kreska ułamkowa zastępuje znak działania.

a) [tex]\frac{8}{1\frac{2}{3} }=8:1\frac{2}{3}=8:\frac{5}{3}=8*\frac{3}{5}=\frac{24}{5}=4\frac{4}{5}[/tex]

b)  [tex]\frac{\frac{1}{2}*\frac{5}{5} }{5}=\frac{5}{12}:5=\frac{5}{12}*\frac{1}{5}=\frac{1}{12}[/tex]

c)   [tex]\frac{\frac{1}{3} }{1\frac{4}{9} }=\frac{1}{3}:1\frac{4}{9}=\frac{1}{3}:\frac{13}{9}=\frac{1}{3}*\frac{9}{13}=\frac{3}{13}[/tex]

d)   [tex]\frac{1}{3}*\frac{1\frac{1}{2} }{\frac{2}{3} }=\frac{1}{3}*\frac{3}{2}:\frac{2}{3}=\frac{1}{3}*\frac{3}{2}*\frac{3}{2}=\frac{3}{4}[/tex]

e)   [tex]\frac{2}{7}:\frac{\frac{1}{7} }{3}=\frac{2}{7}:\frac{1}{7}*\frac{1}{3}=\frac{2}{7}:\frac{1}{21}=\frac{2}{7}* \frac{21}{1} =6[/tex]

Szczegółowe wyjaśnienie:

Magdago

Odpowiedź:

[tex]a)\ \ \dfrac{8}{1\frac{2}{3}}=8:1\frac{2}{3}=8:\frac{5}{3}=8\cdot\frac{3}{5}=\frac{8\cdot3}{5}=\frac{24}{5}=4\frac{4}{5}\\\\\\b)\ \ \dfrac{\frac{1}{2}\cdot\frac{5}{6}}{5}=\dfrac{\frac{5}{12}}{5}=\frac{5}{12}:5=\frac{\not5}{12}\cdot\frac{1}{\not5}=\frac{1}{12}\\\\\\c)\ \ \dfrac{\frac{1}{3}}{1\frac{4}{9}}=\frac{1}{3}:1\frac{4}{9}=\frac{1}{3}:\frac{13}{9}=\frac{1}{\not3_{1}}\cdot\frac{\not9^3}{13}=\frac{3}{13}[/tex]

[tex]d)\ \ \dfrac{13}{2\frac{1}{6}\cdot\frac{3}{4}}=\dfrac{13}{\frac{13}{\not6_{2}}\cdot\frac{\not3^1}{4}}=\dfrac{13}{\frac{13}{8}}=13:\frac{13}{8}=\not13\cdot\frac{8}{\not13}=8\\\\\\e)\ \ \frac{1}{3}\cdot\dfrac{1\frac{1}{2}}{\frac{2}{3}}=\frac{1}{3}\cdot\dfrac{\frac{3}{2}}{\frac{2}{3}}=\frac{1}{3}\cdot(\frac{3}{2}:\frac{2}{3})=\frac{1}{3}\cdot(\frac{3}{2}\cdot\frac{3}{2})=\frac{1}{\not3_{1}}\cdot\frac{\not9^3}{4}=\frac{3}{4}[/tex]

[tex]f)\ \ \frac{2}{7}:\dfrac{\frac{1}{7}}{3}=\frac{2}{7}:(\frac{1}{7}:3)=\frac{2}{7}:(\frac{1}{7}\cdot\frac{1}{3})=\frac{2}{7}:\frac{1}{21}=\frac{2}{\not7_{1}}\cdot\not21^3=2\cdot3=6[/tex]

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