Odpowiedź:
a) HNO₃ - kwas azotowy (V)
mHNO₃= 1g/mol + 14g/mol + 3 × 16g/mol= 1g/mol + 14g/mol + 48g/mol= 63g/mol
b) HNO₂ - kwas arorowy (lll)
mHNO₂ = 1g/mol + 14g/mol + 2 × 16g/mol= 1g/mol + 14g/mol + 32g/mol= 47g/mol
c) H₃PO₄- kwas fosforowy (V)
mH₃PO₄= 3 × 1g/mol + 31g/mol + 4 × 16g/mol= 3g/mol + 31g/mol + 64g/mol= 98g/mol
d) H₃BO₃- kwas borowy(lV)
mH₃BO₃=3 × 1g/mol + 11g/mol + 3 × 16g/mol= 3g/mol + 11g/mol + 48g/mol= 62g/mol
Wyjaśnienie:
