Odpowiedź:
a)
[tex]a_{20} = \frac{3}{5} \times 20 - 6 = 12 - 6 = 6[/tex]
b)
[tex]a_{2k} = \frac{3}{5} \times 2k - 6 = \frac{6}{5} k - 6[/tex]
[tex]a_{n + 1} = \frac{3}{5} (n + 1) - 6 = \frac{3}{5} n + \frac{3}{5} - 6 = \frac{3}{5} n - 5 \frac{2}{5} [/tex]
