[tex]dane:\\m = 10 \ kg \ \ (1 \ l \ wody = 1 \ kg)\\T_1 = 56^{o}C\\T_2 = 36^{o}C\\\Delta T = T_2\\ - T_1 = 36^{o}C - 56^{o}C = -20^{o}C\\c = 4200\frac{J}{kg\cdot^{o}C} \ - \ cieplo \ wlasciwe \ wody\\szukane:\\Q_{oddane} = ?[/tex]
[tex]Q_{oddane} = m\cdot c\cdot \Delta T\\\\Q_{oddane} = 10 \ kg\cdot4200\frac{J}{kg\cdot^{o}C} \cdot(-20^{o}C) = -840 \ 000 \ J\\\\{Q_{oddane} = |-840 \ 000 \ J| =840 \ 000 \ J = 840 \ kJ[/tex]
[tex](1 \ kJ = 1000 \ J)[/tex]
