[tex]e)~~\frac35-(1,4\cdot\frac5{14}-\frac{0,9}{3^2}):(-\frac15)=\frac35-(1\frac25\cdot\frac5{14}-\frac{0,9}{9})\cdot(-\frac51)=\\=\frac35-(\frac75\cdot\frac5{14}-0,1)\cdot(-5)=\frac35-(\frac12-0,1)\cdot(-5)=\\~=\frac35-(\frac5{10}-\frac1{10})\cdot(-5)=\frac35-\frac4{10}\cdot(-5)=\frac35-(-\frac{20}{10})=\frac35+2=2\frac35[/tex]
[tex]f)~~\dfrac{5\frac34-8\frac13}{\frac12-(\frac23)^2}-\frac23:(-\frac4{27})=\dfrac{5\frac9{12}-8\frac4{12}}{\frac12-\frac49}-\frac23\cdot(-\frac{27}4)=\\\dfrac{-2\frac7{12}}{\frac9{18}-\frac8{18}}-(-\frac92)=\dfrac{-2\frac7{12}}{\frac1{18}}+\frac92=-\frac{31}{12}:\frac1{18}+4\frac12=-\frac{31}{12}\cdot\frac{18}1+4\frac12=\\=-\frac{93}2+4\frac12=-46\frac12+4\frac12=-42[/tex]
[tex]g)~~\frac45:(\frac12-\frac15)-(\frac23-(\frac38-1\frac13))=\frac45:(\frac5{10}-\frac2{10})-(\frac{16}{24}-(\frac9{24}-1\frac8{24}))=\\=\frac45:\frac3{10}-(\frac{16}{24}-(-\frac{23}{24}))=\frac45\cdot\frac{10}3-(\frac{16}{24}+\frac{23}{24})=\frac83-\frac{39}{24}=2\frac23-1\frac{15}{24}=\\=2\frac{16}{24}-1\frac{15}{24}=1\frac1{24}[/tex]
[tex]h)~~((-1\frac12)^2-(-1\frac13)^2):4\frac14=((-\frac32)^2-(-\frac43)^2):\frac{17}4=\\=(\frac94-\frac{16}9)\cdot\frac4{17}=(2\frac14-1\frac79)\cdot\frac4{17}=(2\frac{9}{36}-1\frac{28}{36})\cdot\frac4{17}=\frac{17}{36}\cdot\frac4{17}=\frac19[/tex]
