Oblicz:
Pomocyyyy pls

Odpowiedź:
[tex]a) 2^6*(-2)^3:(-2)^8=2^6*(-2^3):2^8=-2^6*2^3:2^8=-2[/tex]
[tex]b)\frac{5^7*(-5)^{24}}{5^{13}*5^{18}}=\frac{5^7*5^{24}}{5^{31}}=\frac{5^{31}}{5^{31}}=1[/tex]
[tex]c)\frac{(-7)^{10}}{7^8*(-7)}=-\frac{7^{10}}{7^9}=-7^1=-7[/tex]
[tex]d)(-\frac{1}{4})^5:0,25^2=-(\frac{1}{4})^5:(\frac{1}{4})^2=-(\frac{1}{4})^3=-\frac{1}{64}[/tex]
[tex]e)(-0,1)^3*0,1^4:0,1^2=-0,1^3*0,1^4:0,1^2=-0,1^5=-(\frac{1}{10})^5=-\frac{1}{100000}[/tex]
[tex]f)\frac{(-0,2)^3*0,2^4*(-0,2)^4}{-(-0,2^4*0,2^6)}=\frac{(-0,2)^3*0,2^4*(-0,2)^4}{-(-0,2^{10})}=\frac{(-0,2)^3*0,2^4*(-0,2)^4}{-(-(\frac{1}{5})^{10})}=\frac{(-0,2)^3*0,2^4*(-0,2)^4}{-(-\frac{1}{5^{10}})}=\frac{(-0,2)^3*0,2^4*(-0,2)^4}{\frac{1}{5^{10}}}=(-0,2)^7*0,2^4*5^{10}=-0,2^7*5^{-4}*5^{10}=-5^{-7}*5^{-4}*5^{10}=-5^{-1}=-\frac{1}{5}[/tex]
Szczegółowe wyjaśnienie: