Witam.
Zad 2
[tex]a) \: \sqrt[3]{ \frac{8}{125} } = \frac{2}{5} [/tex]
[tex]b) \: \sqrt[3]{ \frac{729}{216} } = \frac{9}{6} = \frac{3}{2} = 1 \frac{1}{2} [/tex]
[tex]c) \: \sqrt[3]{ - \frac{64}{343} } = - \frac{4}{7} [/tex]
[tex]d) \: \sqrt[3]{ \frac{2744}{27} } = \frac{14}{3} = 4 \frac{2}{3} [/tex]
[tex]e) \: \sqrt[3]{2 \frac{10}{27} } = \sqrt[3]{ \frac{64}{27} } = \frac{4}{3} = 1 \frac{1}{3} [/tex]
[tex]f) \: \sqrt[3]{ - 15 \frac{5}{8} } = \sqrt[3]{ - \frac{125}{8} } = \frac{5}{2} = 2 \frac{1}{2} [/tex]
[tex]g) \: \sqrt[3]{1 \frac{169}{343} } = \sqrt[3]{ \frac{512}{343} } = \frac{8}{7} = 1 \frac{1}{7} [/tex]
[tex]h) \: \sqrt[3]{5 \frac{23}{64} } = \sqrt[3]{ \frac{343}{64} } = \frac{7}{4} = 1 \frac{3}{4} [/tex]
Zad 3
[tex]a) \: \sqrt[3]{8} + \sqrt[3]{27} - \sqrt[3]{64} = 2 + 3 - 4 = 5 - 4 = 1[/tex]
[tex]b) \: \sqrt[3]{125} \times \sqrt[3]{8} - \sqrt[3]{216} = 5 \times 2 - 6 = 10 - 6 = 4[/tex]
[tex]c) \: \sqrt[3]{1000} - \sqrt[3]{ - 512} \times \sqrt[3]{343} = 10 - ( - 8) \times 7 = 10 + 8 \times 7 = 10 + 56 = 66[/tex]
[tex]d) \: \sqrt[3]{1} - \sqrt[3]{729 } = 1 - 9 = - 8[/tex]
Pozdrawiam,
Michał
