proszę o pomoc w matematyce ułamki

Zadanie 13.
[tex]\frac{4}{5}*\frac{2}{3}+\frac{1}{4}=\frac{8}{15}+\frac{1}{4}=\frac{32}{60}+\frac{15}{60}=\frac{47}{60}[/tex]
[tex]\frac{1}{6}+\frac{3}{8}*1\frac{7}{9}=\frac{1}{6}+\frac{3}{8}*\frac{16}{9}=\frac{1}{6}+\frac{1}{8}*\frac{16}{3}=\frac{1}{6}+\frac{2}{3}=\frac{1}{6}+\frac{4}{6}=\frac{5}{6}[/tex]
[tex]2\frac{3}{7}+\frac{3}{4}*1\frac{1}{3}=\frac{17}{7}+\frac{3}{4}*\frac{4}{3}=\frac{17}{7}+\frac{1}{1}=\frac{17}{7}+\frac{7}{7}=\frac{24}{7}=3\frac{3}{7}[/tex][tex]\frac{1}{9}*\frac{1}{5}+2\frac{1}{2}=\frac{1}{45}+\frac{5}{2}=\frac{2}{90}+\frac{225}{90}=\frac{227}{90}=2\frac{47}{90}[/tex]
[tex]3\frac{3}{4}*(1\frac{3}{4}+\frac{4}{5})=\frac{15}{4}*(\frac{7}{4}+\frac{4}{5})=\frac{15}{4}*(\frac{35}{20}+\frac{16}{20})=\frac{15}{4}*\frac{51}{20}=\frac{3}{4}*\frac{51}{4}=\frac{153}{16}=9\frac{9}{16}[/tex]
[tex](2\frac{1}{2}+\frac{1}{3})*2\frac{2}{17}=(\frac{5}{2}+\frac{1}{3})*\frac{36}{17}=(\frac{15}{6}+\frac{2}{6})*\frac{36}{17}=\frac{17}{6}*\frac{36}{17}=6[/tex]
Zadanie 1.
[tex]1\frac{4}{7}*4\frac{2}{3}=\frac{11}{7}*\frac{14}{3}=\frac{11}{1}*\frac{2}{3}=\frac{22}{3}=7\frac{1}{3}[/tex]
Zadanie 2.
[tex]2\frac{8}{11}*1\frac{3}{8}=\frac{30}{11}*\frac{11}{8}=\frac{30}{8}=3\frac{6}{8}=3\frac{3}{4}[/tex]
[tex]2\frac{2}{13}*1\frac{3}{10}=\frac{28}{13}*\frac{13}{10}=\frac{28}{10}=2\frac{8}{10}=2\frac{4}{5}[/tex]
Zadanie 3.
[tex]1\frac{1}{5}*1\frac{2}{5}=\frac{6}{5}*\frac{7}{5}=\frac{42}{25}=1\frac{17}{25}[/tex]
[tex]2\frac{5}{7}*2\frac{6}{7}=\frac{19}{7}*\frac{20}{7}=\frac{380}{49}=7\frac{37}{49}[/tex]
[tex]3\frac{4}{5}*5\frac{3}{4}=\frac{19}{5}*\frac{23}{4}=\frac{437}{20}=21\frac{17}{20}[/tex]
[tex]12\frac{1}{10}*9\frac{1}{10}=\frac{121}{10}*\frac{91}{10}=\frac{11011}{100}=110\frac{11}{100}[/tex]
[tex]8\frac{1}{8}*2\frac{2}{5}=\frac{65}{8}*\frac{12}{5}=\frac{13}{2}*\frac{3}{1}=\frac{39}{2}=19\frac{1}{2}[/tex]