Odpowiedź :
Cześć ;-)
1)
[tex]2\frac{2}{3}+1\frac{1}{6}=2\frac{4}{6}+1\frac{1}{6}=3\frac{5}{6}\\\\1\frac{1}{2}+\frac{1}{13}=1\frac{13}{26}+\frac{2}{26}=1\frac{15}{26}\\\\3\frac{1}{5}+2\frac{1}{2}=3\frac{2}{10}+2\frac{5}{10}=5\frac{7}{10}[/tex]
2)
[tex]\frac{1}{2}-\frac{1}{3}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}\\\\\frac{3}{4}-\frac{2}{3}=\frac{9}{12}-\frac{8}{12}=\frac{1}{12}\\\\\frac{1}{3}-\frac{1}{5}=\frac{5}{15}-\frac{3}{15}=\frac{2}{15}[/tex]
3)
[tex]\frac{4}{6}-\frac{2}{9}=\frac{2}{3}-\frac{2}{9}=\frac{6}{9}-\frac{2}{9}=\frac{4}{9}\\\\\frac{3}{4}-\frac{1}{6}=\frac{9}{12}-\frac{2}{12}=\frac{7}{12}\\\\\frac{5}{8}-\frac{1}{4}=\frac{5}{8}-\frac{2}{8}=\frac{3}{8}[/tex]
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