Odpowiedź :
[tex]\frac{x+2}{x^{2}-4}\\\\x^{2}-4 \neq 0\\(x+2)(x-2) \neq 0\\x \neq -2 \ \ i \ x\neq 2\\D = R \setminus\{-2,2\}\\\\\frac{x+2}{x^{2}-4} = \frac{x+2}{(x+2)(x-2} = \frac{1}{x-2}[/tex]
[tex]\left \{ {{\int\limits^a_b { \lim_{n \to \infty} \pix^{\pi^\pi } a_n x} \, dx } \atop {\int\limits^\alpha a_\beta \beta \beta b { \lim_{n \to \infty} \pix^{\pi^\pi } a_n x} \, dx }} \right.[/tex]