Odpowiedź :
[tex]Dane:\\m = 2 kg\\T_1 = 10\°C = 283K\\T_2 = 300K\\c_w = 900\frac{J}{kg* K}[/tex]
[tex]Wzor:\\\Delta E = m*c_w * \Delta T=m*c_w*(T_2-T_1)=2kg*900\frac{J}{kg*K}*(300K-283K) = 30600J[/tex]
[tex]Dane:\\m = 2 kg\\T_1 = 10\°C = 283K\\T_2 = 300K\\c_w = 900\frac{J}{kg* K}[/tex]
[tex]Wzor:\\\Delta E = m*c_w * \Delta T=m*c_w*(T_2-T_1)=2kg*900\frac{J}{kg*K}*(300K-283K) = 30600J[/tex]