Odpowiedź :
[tex]sin60^{o} = \frac{\sqrt{3}}{2}\\\\cos60^{o} = \frac{1}{2}\\\\tg60^{o} = \sqrt{3}\\\\ctg60^{o} = \frac{\sqrt{3}}{3}[/tex]
[tex]sin60^{o} = \frac{\sqrt{3}}{2}\\\\cos60^{o} = \frac{1}{2}\\\\tg60^{o} = \sqrt{3}\\\\ctg60^{o} = \frac{\sqrt{3}}{3}[/tex]