Odpowiedź :
1.
[tex]5\frac{m}{s} = 5\cdot\frac{\frac{1}{1000}km}{\frac{1}{3600}{h}} = 5\cdot3,6 \ \frac{km}{h} = 18\frac{km}{h}[/tex]
2.
[tex]108\frac{km}{h} = 108\cdot\frac{1000 \ m}{3600 \ s} = 30\frac{m}{s}[/tex]
3.
[tex]dane:\\t = 5 \ min = \frac{5}{60} \ h = \frac{1}{12} \ h\\v = 24\frac{km}{h}\\szukane:\\s = ?\\\\s = v\cdot t\\\\s = 24\frac{km}{h}\cdot\frac{1}{12} \ h = 2 \ km[/tex]
4.
[tex]dane:\\v_1 = 60\frac{km}{h}\\t = 5 \ s\\v_2 = 74,4\frac{km}{h}\\szukane:\\a = ?\\\\a = \frac{\Delta v}{t}\\\\\Delta v = v_2 - v_1 = 74,4\frac{km}{h}-60\frac{km}{h} = 14,4\frac{km}{h} = 14,4\cdot\frac{1000 \ m}{3600 \ s} = 4\frac{m}{s}\\\\a = \frac{4\frac{m}{s}}{5 \ s} = 0,8\frac{m}{s^{2}}[/tex]
5.
[tex]dane:\\v_{o} = 0\\t = 10 \ s\\a = 1,8\frac{m}{s^{2}}\\szukane:\\s = ?\\\\s = \frac{1}{2}at^{2}\\\\s = \frac{1}{2}\cdot1,8\frac{m}{s^{2}}\cdot(10 \ s)^{2} = 90 \ m[/tex]