Zadanie w załączniku, szybko, dzieki

a) [tex]\sqrt{24} = \sqrt{4} \cdot \sqrt{6} = 2\sqrt{6}[/tex]
a = 6
b) [tex]\sqrt{24} = \sqrt{8} \cdot \sqrt{3} = 2\sqrt{2} \cdot \sqrt{3}[/tex]
b = [tex]2\sqrt{2}[/tex]
c)
[tex]c\sqrt{24} = \sqrt{2} \\c \cdot 2\sqrt{6} = \sqrt{2} \\c=\frac{\sqrt{2} }{2\sqrt{6} } \\c=\frac{1}{2\sqrt{3} } \\\frac{1}{2\sqrt{3} } \cdot \frac{\sqrt{3} }{\sqrt{3} } = \frac{\sqrt{3} }{6} \\c = \frac{\sqrt{3} }{6}[/tex]
d)
[tex]2\sqrt{d} = \sqrt{3} \\\sqrt{d} = \frac{\sqrt{3} }{2}[/tex]
podnosimy obie strony do kwadratu
[tex]d=\frac{3}{4}[/tex]