Odpowiedź :
[tex]V_r=100 \ cm^3\\\\d_r=1,16 \ \frac{g}{cm^3}\\\\m_r=V_r\cdot d_r=100 \ cm^3\cdot1,16 \ \frac{g}{cm^3}=116 \ g\\\\C_p=17\%\\\\m_s=0,17\cdot116 \ g=\boxed{19,72 \ g \ \text{NaOH}}[/tex]
[tex]V_r=100 \ cm^3\\\\d_r=1,16 \ \frac{g}{cm^3}\\\\m_r=V_r\cdot d_r=100 \ cm^3\cdot1,16 \ \frac{g}{cm^3}=116 \ g\\\\C_p=17\%\\\\m_s=0,17\cdot116 \ g=\boxed{19,72 \ g \ \text{NaOH}}[/tex]