Odpowiedź :
Odpowiedź:
[tex]a)\ \ \sqrt{7^2}+\sqrt{6}-(\sqrt{6})^2=7+\sqrt{6}-6=1+\sqrt{6}\\\\b)\ \ \sqrt[3]{12^3}-(\sqrt{17})^2-\sqrt{5}=12-17-\sqrt{5}=-5-\sqrt{5}\\\\c)\ \ 3\sqrt{5^2}+2\sqrt{5}-2\sqrt[3]{(-5)^3}=3\cdot5+2\sqrt{5}-2\cdot(-5)=15+2\sqrt{5}+10=25+2\sqrt{5}\\\\d)\ \ -\sqrt[3]{5^3}-\sqrt[3]{7}-\sqrt[3]{-7}=-5-\sqrt[3]{7}-(-\sqrt[3]{7})=-5-\sqrt[3]{7}+\sqrt[3]{7}=-5[/tex]