[tex]x^{2} - 2( x+ 3) = 3\\x^{2} -2x - 6 = 3\\x^{2} -2x -9 =0\\delta\\4 + 36 = 40\\\sqrt{40} = 2\sqrt{10} \\x1= \frac{ 2\sqrt{10} + 2}{2} = \sqrt{10} + 1\\x2 = \frac{ 2\sqrt{10} - 2}{2}= \sqrt{10} -1[/tex]
3.
[tex]x^{2} - 7x + 12 > 0\\delta\\49 -48= 1 \\\sqrt{1} = 1\\x1 = \frac{7 - 1}{2} = 3\\x2 = \frac{7 + 1}{2}= 4\\x[/tex]x∈ ( -∞, 3) ( 4, ∞)
