Odpowiedź:
Wyjaśnienie:
Dane: Szukane:
Ka = 1,8*10⁻⁵ pH =?
Cp = 5%
d =1g/cm³ = 1000g/dm³
CH₃COOH ⇄ CH₃COO⁻ + H⁺
K = [CH₃COO⁻]*[H⁺]/[CH₃COOH]
[CH₃COO⁻] = [H⁺]
[CH₃COOH] = Cm
K = [H⁺]²/Cm
Cm = Cp*d/M*100%
M kwasu = 60g/mol
Cm = 5%*1000/60*100%
Cm = 0,83mol/dm³
K = [H⁺]²/0,83
[H⁺] = √K*0,83
[H⁺] = 1,22*10⁻³
pH = -log( 1,22*10⁻³)
pH = 2,91
