Odpowiedź:
[tex]a)\\\\2(x+4)=-3(2x-4)\\\\2x+8=-6x+12\\\\2x+6x=12-8\\\\8x=4\ \ /:8\\\\x=\frac{4}{8}\\\\x=\frac{1}{2}\\\\\\b)\\\\\frac{2}{5}x+10=\frac{1}{5}-2x\ \ /\cdot5\\\\2x+50=1-10x\\\\2x+10x=1-50\\\\12x=-49\ \ /:12\\\\x=-\frac{49}{12}\\\\x=-4\frac{1}{12}[/tex]
[tex]c)\\\\\frac{3}{7}x+2=-4x\ \ /\cdot7\\\\3x+14=-28x\\\\3x+28x=-14\\\\31x=-14\ \ /:31\\\\x=-\frac{14}{31}\\\\\\d)\\\\12x-9=-4(x+9)\\\\12x-9=-4x-36\\\\12x+4x=-36+9\\\\16x=-27\ \ /:16\\\\x=-\frac{27}{16}\\\\x=-1\frac{11}{16}[/tex]
[tex]e)\\\\4x-5=\frac{1}{3}x+4\ \ /\cdot3\\\\12x-15=x+12\\\\12x-x=12+15\\\\11x=27\ \ /:11\\\\x=\frac{27}{11}\\\\x=2\frac{5}{11}\\\\\\f)\\\\4x-6=\frac{3}{4}\ \ /\cdot4\\\\16x-24=3\\\\16x=3+24\\\\16x=27\ \ /:16\\\\x=\frac{27}{16}\\\\x=1\frac{11}{16}[/tex]
[tex]g)\\\\-4(x+5)=-7(2x-9)\\\\-4x-20=-14x+63\\\\-4x+14x=63+20\\\\10x=83\ \ /:10\\\\x=\frac{83}{10}\\\\x=8\frac{3}{10}[/tex]
