[tex](4x {}^{2} - 2x + 1)(2x + 1) = 28[/tex]
[tex]8x {}^{3} + 1 = 28[/tex]
[tex]8x {}^{3} = 28 - 1[/tex]
[tex]8x {}^{3} = 27 \: \: \: \: \: ( \div 8[/tex]
[tex]x {}^{3} = \frac{27}{8} [/tex]
[tex]x {}^{3} = ( \frac{3}{2} ) {}^{3} [/tex]
[tex]x = \frac{3}{2} = 1 \frac{1}{2} [/tex]
Mam nadzieję że pomogłam ❤️
